Title: 1. Combinations of arithmetic operations
Course: Demonstrating STACK (v4.3.7)

\([value]+\left( -[value] \right)=\)

Leave your answer as a single integer.
Feedback: Remember that adding a negative number is the same as subtraction. So in this example: \([value]+\left( -[value] \right) = [value]-[value] = [value]\).

\([value]- \left([value] \right)=\)

Leave your answer as a single integer.
Feedback: Remember that subtracting a negative number is the same as adding. So in this example: \([value]- \left([value] \right)\) = [value] + [value] = [value].

\(\left( [value] \right) \cdot \left( [value] \right)=\)

Leave your answer as a single integer.
Feedback: Remember that multiplying two negative numbers gives a positive number: \( \left([value] \right)\cdot \left([value] \right)\) = \([value]\cdot[value] = [value].\)

\([value]\cdot \left( [value] \right)=\)

Express your answer as a single integer.
Feedback: Remember that multiplying a positive and a negative number gives a negative number: \([value] \cdot \left([value]\right) = [value]\).

Simplify the algebraic expression \[[value].\] Be sure to leave your answer in the form: \(x^y\).
Feedback: Remember the rule that the rule, \(c^a+c^b=c^{a+b}\). In this exmaple: \[c^[value]+c^[value]=c^[value].\]

\({\left( [value]^[value] \right)}^[value]\) can be expressed in the form:
\[[value]^x.\] Find the value of \(x\).

\(x\) =
Feedback: Remember the rule that \(\left( c^a \right)^b=c^{ab}\). In this example \(\left([value]^[value] \right)^[value]\) = \([value]^{[value]\cdot[value]}\). Therefore: \[x = [value] \cdot [value] = [value].\]

\([value]^0\)=
Feedback: Remember that \(x^0=1\) for all \(x \neq 0\). Therefore \([value]^0=1\).